Solutions to Web Experiment: Chemical Equilibrium II
Web Experiment: Chemical Equilibirum II
Answers to Questions
- A (4.0 mol/L) and B (4.0 mol/L) are allowed to react and the equilibrium molarities of A, B, and C are obtained from the plots of molarity versus time.
The initial and equilibrium molarities of A, B, and C are entered in the equilibrium table.
Note that the entries in the table are molarities (mol/L).
Since
then
and
Note that changes in the molarities of A, B, and C are related by mole ratios.
- After 8 seconds the molarities of A, B, and C no longer change with time. The reaction is at equilibrium.
- When the initial molarities of A, B, and C are 1.0, 1.0, and 3.0 mol/L at 25ºC, the molarities do not change with time. The system is at equilibrium.
- Since Kc (3.0054 1/M) > 1, the equilibrium is said to lie to the right.
- In exercise #1 the equilibrium molarities of A, B, and C are 1.0, 1.0, and 3.0 mol/L at 25ºC. The addition of 1.0 mol/L of B to this equilibrium results in a decrease in the molarities of A and B and an increase in the molarity of C (see plots of molarity versus time). After 7 seconds the system is again at equilibrium and the new equilibrium molarities of A, B, and C are 0.7, 1.7, and 3.3 mol/L. When 1.0 mol/L of B is added to the equilibrium, the reaction proceeds to the right to reestablish the equilibrium. Moles of A and B are consumed and moles of C are produced.
- When 1.0 mol/L of C is added to the equilibrium in exercise #1, the molarities of A and B increase and the molarity of C decreases with time (see plots of molarity versus time). After 7 seconds the system is again at equilibrium and the new equilibrium molarities of A, B, and C are 1.1, 1.1, and 3.9 mol/L. When 1.0 mol/L of C is added to the equilibrium, the reaction proceeds to the left to reestablish the equilibrium. Moles of C are consumed and moles of A and B are produced.
- When 1.0 mol/L of A and 1.0 mol/L of C are added to the equilibrium in exercise #1, the molarities of A and B decrease and the molarity of C increases with time (see plots of molarity versus time). After 7 seconds the system is again at equilibrium and the new equilibrium molarities of A, B, and C are 1.8, 0.8, and 4.2 mol/L. When 1.0 mol/L of A and 1.0 mol/L of A are added to the equilibrium, the reaction proceeds to the right to reestablish the equilibrium. Moles of A and B are consumed and moles of C are produced.
- When heat is added to the equilibrium in exercise #1 and the temperature is raised to 386 K, the molarities of A and B increase and the molarity of C decreases with time (see plots of molarity versus time). After 3 seconds the system is again at equilibrium and the new equilibrium molarities of A, B, and C are 1.4, 1.4, and 2.6 mol/L. In this case the value of Kc changes. When the temperature is increased, the value of Kc decreases and the equilibrium shifts to the left. Moles of C are consumed and moles of A and B are produced.
- When a system is in equilibrium, a change in any one of the factors upon which the equilibrium depends will cause the equilibrium to shift in such a way as to diminish the effect of the change. To diminish the effect of the added heat, the reaction proceeds in the direction that consumes heat. Since moles of C were consumed and moles of A and B were produced, heat is consumed when the reaction goes in the reverse direction,
i.e. heat is required for C to dissociate into A and B. Therefore, heat is released when the A and B combine to form C and the forward reaction
is exothermic.